Источник:
http://www.agermark.com/2015/02/sele...-distinct.html
==============
The Select statement doesn't have a way let you do a count of distinct records.
Today I found this neat way to do it anyway, in the method \Data Dictionary\Tables\LedgerJournalTable\Methods\numOfVouchers:
...
sql = 'select count(distinct %1) from %2 where %3 = %4 and %5 = %6 and %7 = %8';
sql = strFmt(sql,
ReleaseUpdateDB::backendFieldName(tableNum(LedgerJournalTrans), fieldNum(LedgerJournalTrans, Voucher)),
ReleaseUpdateDB::backendTableName(tableNum(LedgerJournalTrans)),
ReleaseUpdateDB::backendFieldName(tableNum(LedgerJournalTrans), fieldNum(LedgerJournalTrans, JournalNum)),
sqlSystem.sqlLiteral(this.JournalNum),
ReleaseUpdateDB::backendFieldName(tableNum(LedgerJournalTrans), fieldNum(LedgerJournalTrans, DataAreaId)),
sqlSystem.sqlLiteral(ledgerJournalTrans.DataAreaId),
ReleaseUpdateDB::backendFieldName(tableNum(LedgerJournalTrans), fieldNum(LedgerJournalTrans, Partition)),
getcurrentpartitionrecid());
...
Источник:
http://www.agermark.com/2015/02/sele...-distinct.html